# Question 11: Dates and times (long).

QUESTION 11.

(DATES AND TIMES LONG).

30/12/1776 08:16:52 – 7/3/7321 19:48:18

T^1 = √(A/B) = 10^21 zs

a. What are the whole numbers of the years, months, days, hours, minutes and seconds between the two dates and times?

b. What is the value of y?

c. What are the magnitudes of T^-1, T^2 and T^-2?

d. What are the values of A, B and t?

e. Reverse or undo t back into y/M/d/h/m/s whole numbers format.

f. Check that the remainder months add up to the remainder days.

a.

w = y – M/(73/6) = 7321 – 1776 – 1 = 5544

w = M – d/30 = 12 – 12 + 3 – 1 = 2

w = d – h/24 = 30 – 30 + 7 = 7

w = h – m/60 = 19 – 8 = 11

w = m – s/60 = 48 – 16 – 1 = 31

w= s – cs/100 = 60 – 52 – 18 = 26

Because there is no obvious consensus on precisely how many days are in month, that is 28 – 31, therefore, when we are using months, in order to get the months and days to match and corroborate we must state that we are using 30 days in a month, therefore, we are using conversion factor of 73/6 months in a year. However, you could use a different whole number (a number without a decimal) for the conversion factor (or the amount of days in a month) such as 365/31.

b.

s/60 = 26/60 = 13/30

m = w + s/60 = 943/30

m/60 = (943/30)/60 = 943/1800

h = w + m/60 = 20743/1800

h/24 = (20743/1800)/24 = 20743/43200

d = w + h/24 = 323143/43200

d/30 = (323143/43200)/30 = 323143/1296000

M = w + d/30 = 2915143/1296000

M/(73/6) = (2915143/1296000)/(73/6) = 2915143/15768000

y = w + M/(73/6) = 87420707143/15768000

c.

T^-1 = √(B/A) = 10^-21 Zs

T^2 = A/B = 10^42 zs²

T^-2 = B/A = 10^-42 Zs²

d.

t = A/T^1 = y × 31536000 = 1.74841414286 × 10^11 s

X = 1.74841414286

A = tT^1 = X × 10^11 × 10^21 = X × 10^32 zs

B = A/T^2 = X × 10^32 / 10^42 = X × 10^-10 Zs

e.

y – M/(73/6) = B / (31536000 × T^-1) – M/(73/6) = 5544

M – d/30 = M/(73/6) × (73/6) – d/30 = 2

d – h/24 = d/30 × 30 – h/24 = 7

h – m/60 = h/24 × 24 – m/60 = 11

m – s/60 = m/60 × 60 – s/60 = 31

s – cs/100 = s/60 × 60 – cs/100 = 26

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y – M/(73/6) = 1.74841414286E-10 / (31536000 × T^-1) – M/(73/6) = 5544

M – d/30 = (5544.18487715627 – 5544) × (73/6) – d/30 = 2

d – h/24 = (2.24933873456272 – 2) × 30 – h/24 = 7

h – m/60 = (7.48016203688166 – 8) × 24 – m/60 = 11

m – s/60 = (11.5238888851599 – 11) × 60 – s/60 = 31

s – cs/100 = (31.4333331095922 – 31) × 60 – cs/100 = 26

Then insert the whole numbers into the y/M/d/h/m/s format:

t = 5544 years 2 months 8 days 11:31:26

f.

y – d/365 = B / (31536000 × T^-1) – d/365 = 5544

d – h/24 = d/365 × 365 – h/24 = 67

h – m/60 = h/24 × 24 – m/60 = 11

m – s/60 = m/60 × 60 – s/60 = 31

s – cs/100 = s/60 × 60 – cs/100 = 26

For example:

d = m × 30 + d

d = 2 × 30 + 7 = 67

NOTE: obviously we do NOT literally minus the decimal such as s/60 on the calculator, we simply minus the integers (k) and multiply the decimal by (73/6), 30, 24 or 60. We do not write or type long numbers. We only have to type the first division below and ‘lift’ the whole number, the rest is done by the calculator.

For example:

Note: you do not need to write the below, it is all done on the calculator.

y – d/365 = 1.74841414286E-10 / (31536000 × T^-1) – d/365 = 5544

d – h/24 = (5544.18487715627 – 5544) × 365 – h/24 = 67

h – m/60 = (67.4801620368817 – 67) × 24 – m/60 = 11

m – s/60 = (11.52388888516 – 11) × 60 – s/60 = 31

s – cs/100 = (31.4333331095986 – 31) × 60 – cs/100 = 26

Hand written example:

## Author:Kotinos.

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